## If inequality 2x-m is less than or equal to 0 and there are only three positive integer solutions, find the value range of positive integer M Why can a positive integer only be 123? A positive integer is 4, 5, 6, no?

2X - m less than or equal to 0

2x≤M

x≤M/2

Because: there are only three positive integer solutions, X can only be: 1,2,3

3≤M/2

### If there are four positive integer solutions of inequality 2x-3 ≤ m, the value range of M is __

2x-3≤m，

2x≤m+3，

x≤m+3

2，

∵ there are four positive integer solutions to this inequality,

The positive integer solution of the inequality is 1, 2, 3, 4,

∴4≤m+3

2＜5，

The value range of M is 5 ≤ m ＜ 7

Therefore, the answer is: 5 ≤ m < 7

### If inequality group 3−2x≥0 x≥m If there is a solution, the value range of M is () A. m＜3 two B. m≤3 two C. m＞3 two D. m≥3 two

3−2x≥0①

x≥m② From ①: X ≤ 3

two

From ②: X ≥ M

The solution set is m ≤ x ≤ 3

two

∴m≤3

2．

Therefore, B

### If there are four integer solutions for the inequality system x-m > 0,7-2x less than or equal to 1, what is the value range of M? need

You have a problem,

x-m>0 => x>m

7-2x x>= 3

I can't push it out. It's all bigger than the size

If the first expression is initially less than the sign, then the value range of M is 6 < M

### If the positive integer solution of inequality 3x-a ≤ 0 is 1, 2, 3, then the value range of a is __

Solve the inequality 3x-a ≤ 0 and get x ≤ a

3，

∵ the positive integer solution of the inequality is 1, 2, 3,

∴3≤a

3＜4，

The solution is 9 ≤ a < 12

Therefore, the answer is: 9 ≤ a ＜ 12

### If the positive integer solution of inequality 3x-a ≤ 0 is 1, 2, 3, then the value range of a is __

Solve the inequality 3x-a ≤ 0 and get x ≤ a

3，

∵ the positive integer solution of the inequality is 1, 2, 3,

∴3≤a

3＜4，

The solution is 9 ≤ a < 12

Therefore, the answer is: 9 ≤ a ＜ 12