If inequality 2x-m is less than or equal to 0 and there are only three positive integer solutions, find the value range of positive integer M Why can a positive integer only be 123? A positive integer is 4, 5, 6, no?

2X - m less than or equal to 0
2x≤M
x≤M/2
Because: there are only three positive integer solutions, X can only be: 1,2,3
3≤M/2

If there are four positive integer solutions of inequality 2x-3 ≤ m, the value range of M is __

2x-3≤m，
2x≤m+3，
x≤m+3
2，
∵ there are four positive integer solutions to this inequality,
The positive integer solution of the inequality is 1, 2, 3, 4,
∴4≤m+3
2＜5，
The value range of M is 5 ≤ m ＜ 7
Therefore, the answer is: 5 ≤ m < 7

If inequality group 3−2x≥0 x≥m If there is a solution, the value range of M is () A. m＜3 two B. m≤3 two C. m＞3 two D. m≥3 two

3−2x≥0①
x≥m② From ①: X ≤ 3
two
From ②: X ≥ M
The solution set is m ≤ x ≤ 3
two
∴m≤3
2．
Therefore, B

If there are four integer solutions for the inequality system x-m > 0,7-2x less than or equal to 1, what is the value range of M? need

You have a problem,
x-m>0 => x>m
7-2x x>= 3
I can't push it out. It's all bigger than the size
If the first expression is initially less than the sign, then the value range of M is 6 < M

If the positive integer solution of inequality 3x-a ≤ 0 is 1, 2, 3, then the value range of a is __

Solve the inequality 3x-a ≤ 0 and get x ≤ a
3，
∵ the positive integer solution of the inequality is 1, 2, 3,
∴3≤a
3＜4，
The solution is 9 ≤ a < 12
Therefore, the answer is: 9 ≤ a ＜ 12

If inequality 2x-m is less than or equal to 0 and there are only three positive integer solutions, find the value range of positive integer M Why can a positive integer only be 123? A positive integer is 4, 5, 6, no?