A group of ions that can coexist in large quantities in the following solutions are A. In the solution with pH = 1: NH4 +, Fe2 +, sulfate, chloride ion B. Solution of excess sulfur dioxide gas: iron ion, nitrate, barium ion and hydrogen ion C. In the solution with aluminum ion concentration of 0.1mol/l: sodium ion, potassium ion, metaaluminate ion and sulfate D. In the solution with hydrogen ion concentration of 1 * 10 ^ - 13mol / L ionized by water: sodium ion, bicarbonate ion, chloride ion and bromine ion

A group of ions that can coexist in large quantities in the following solutions are A. In the solution with pH = 1: NH4 +, Fe2 +, sulfate, chloride ion B. Solution of excess sulfur dioxide gas: iron ion, nitrate, barium ion and hydrogen ion C. In the solution with aluminum ion concentration of 0.1mol/l: sodium ion, potassium ion, metaaluminate ion and sulfate D. In the solution with hydrogen ion concentration of 1 * 10 ^ - 13mol / L ionized by water: sodium ion, bicarbonate ion, chloride ion and bromine ion

A. In the solution with pH = 1: NH4 +, Fe2 +, sulfate, chloride ion
can
B. Solution of excess sulfur dioxide gas: iron ion, nitrate, barium ion and hydrogen ion
It cannot react with iron ion + SO2, SO2 + nitrate + hydrogen ion
C. In the solution with aluminum ion concentration of 0.1mol/l: sodium ion, potassium ion, metaaluminate ion and sulfate
Aluminum hydroxide cannot be generated from aluminum ion + metaaluminate ion + water
D. In the solution with hydrogen ion concentration of 1 * 10 ^ - 13mol / L ionized by water: sodium ion, bicarbonate ion, chloride ion and bromine ion
Bicarbonate ions cannot react with both hydrogen ions or hydroxyl ions

Ion coexistence in solution after adding sufficient Na2O2 Why can't Na + Ba2 + AlO2 - I - coexist in a large amount in the solution after adding enough Na2O2? Is it because of the strong oxidation of NaO2 and the reducibility of I -?

Sodium peroxide reacts with water to produce hydrogen peroxide, which can oxidize iodine ions into iodine
Na2O2 + 2H2O = = 2naoh + H2O2 hydrogen peroxide is an intermediate product, which is unstable and will decompose. However, it does exist, so it can oxidize iodine ions

The ion group that can still coexist in a large amount after adding enough Na2O2 to the solution is () A. NH4+Ba2+    Cl-    NO3- B. K+   AlO2-   Cl-   SO42- C. Ca2+    Mg2+   NO3-   HCO3- D. Na+   Cl-   CO32-   SO32-

A. When enough Na2O2 is added to the solution to generate NaOH, it can not coexist with NH4 + to form a weak electrolyte, so a is wrong;
B. This group of ions can coexist if they do not react in alkaline solution, so B is correct;
C. Add enough Na2O2 to the solution to generate NaOH. NaOH reacts with HCO3 - to generate water and carbonate ions, which cannot coexist, so C error;
D. Na2O2 has strong oxidizability. If there is a redox reaction with SO32 - ions, the ions cannot coexist, so D error;
Therefore, B

The ion group that must coexist in the following solutions is A contains a lot of aluminum ions: sodium ion, ammonium ion, sulfate ion and chloride ion B containing a large amount of ferric ions: sodium ion, magnesium ion, nitrate ion, SCN2-

A.
The trivalent iron ion in B will combine with SCN - (not SCN2 bar!) to form a complex that is difficult to ionize. (not a redox reaction)

In the following solutions, each group of ions must be able to coexist in large quantities () A. Solution to turn phenolphthalein test solution Red: Na +, Cl -, SO42 -, Fe3+ B. Solution for turning purple litmus test solution Red: Fe2 +, Mg2 +, NO3 -, CL- C. C (H +) = 10-12mol • L-1 solution: K +, Ba2 +, Cl -, br- D. Sodium bicarbonate solution: K +, SO42 -, Cl -, H+

A. The solution that turns phenolphthalein test solution red is alkaline and cannot contain a large amount of Fe3 +, so a is wrong;
B. The solution that turns purple litmus test solution red is acidic, and redox reaction occurs between Fe2 +, H +, NO3 - ions, which cannot coexist in large quantities, so B is wrong;
C. The solution with C (H +) = 10-12mol • L-1 is alkaline. This group of ions do not react and can coexist in large quantities, so C is correct;
D. Bicarbonate ions react with hydrogen ions to generate water and gas, which cannot coexist in large quantities, so D error;
Therefore: C

The following groups of ions can coexist in large quantities in aqueous solution is () A. Fe2+、Ca2+、CO32-、OH- B. Na+、SO42-、Cl-、OH- C. Ba2+、H+、Cl-、OH- D. Ag+、NH4+、NO3-、OH-

A. Because Fe2 + and oh - can generate ferrous hydroxide precipitation, and CO32 - and Ca2 + can generate calcium carbonate precipitation, a is wrong; B. Since there is no water, precipitation or gas in the combination of cation and anion, these four ions can coexist in large quantities in aqueous solution, so B is correct; C. Because H + and oh - combine to form water, C error