The density of the mixed gas composed of carbon dioxide, hydrogen and carbon monoxide is the same as that of nitrogen at the same temperature and pressure. Then the volume ratio of carbon dioxide, hydrogen and carbon monoxide in the mixed gas is () A. 29：8：13 B. 22：1：14 C. 13：8：29 D. 26：16：57

The density of the mixed gas composed of carbon dioxide, hydrogen and carbon monoxide is the same as that of nitrogen at the same temperature and pressure. Then the volume ratio of carbon dioxide, hydrogen and carbon monoxide in the mixed gas is () A. 29：8：13 B. 22：1：14 C. 13：8：29 D. 26：16：57

The density of the mixed gas composed of carbon dioxide, hydrogen and carbon monoxide is the same as that of nitrogen at the same temperature and pressure. It can be seen that the average relative molecular weight of the mixed gas is equal to the relative molecular weight of nitrogen, which is 28, while the relative molecular weight of carbon monoxide is also 28, so the average relative molecular weight of carbon dioxide and hydrogen is 28

There are three problems. Just help me solve one problem. I need to write the problem-solving process, The mass fraction of solute in commercial concentrated sulfuric acid is 98% and the density is 1.84g/ml. The quantity and concentration of solute are calculated. In a hurry, I forget ==|||

Solving this problem requires a formula (several basic formulas are derived)
c=1000pa%/M
Where: C represents the amount of substance (mol)
P is the density of the solution (g / ml)
A% is the mass fraction
M is the molar mass of solute (g / mol)
Just algebra yourself according to the formula

At a certain temperature, the following substances are fully burned in sufficient oxygen, the product completely reacts with excess sodium peroxide, and the solid weight of sodium peroxide increases WG. Those meeting this requirement are () 　　① H2　； ②CO　； ③ CO and H2; ④HCOOCH3　； ⑤ HOOC－COOH A. all B. only ④ and ⑤ C. only ① ② ③ D. except ⑤ Please attach a detailed explanation,

In fact, we should first know that the increased weight is the amount of initial reactant, which means that there is no gas and water, and then start writing the reaction equation. Note that it is the general reaction equation, such as ①: 2 H2 + O2 = 2 H2O (1), 2 Na2O2 + 2 H2O = 4 Na2O2 + O2 (2). Replace (1) with (2) to get 2 H2 + O2

(1) Remove impurities MgCl2 and Na2SO4 mixed in NaCl, and select reagent: A：NaOH.BaCL2 B":Na2CO3,BaCL2 (2) Avogadro constant, molar mass and molar volume of substance are known. The approximate values of the following physical quantities cannot be calculated completely: A. Molecular size and mass of solid matter B. Molecular size and mass of liquid substances C. Size and mass of gas molecules D. Molecular mass of gaseous substances (3) Reaction equation of potassium bisulfate with potassium carbonate and potassium hydroxide (4) It is known that there is 500 ml of concentrated sulfuric acid with a density of 1.84 g / ml and a mass fraction of 98%. Q: is the mass concentration of the solution obtained by mixing the sulfuric acid with water of the same mass greater than 9.2 mol / L (5) The ratio of the number of atoms of cl-35 and cl-37 in Cl2 to that of cl-35 and cl-37 in HCl The ratio of the number of atoms of cl-37 is equal. Why? The answer is already known, mainly want to know the process!

1. A. do not bring in other ions. Carbonate ions are brought in option B. 2. C. solid and liquid molecules are very close and can be considered adjacent. However, there is a large distance between gas molecules, and the volume of gas molecules cannot be calculated by dividing the total volume of gas by the number of molecules. 3.2khso4 + 2k2co3 = 2k2so4 + K2CO3 + H2O + CO2 (

Redox reaction calculation! 24L Na2SO3 solution with a concentration of 0.05mol/l exactly reacts with 20L K2Cr2O7 solution with a concentration of 0.02mol/l. It is known that Na2SO3 is oxidized to Na2SO4 by K2Cr2O7, so the valence of element Cr in the reduction product is (+ 3)

This is a simple calculation of the conservation of gain and loss electrons. I will write the solution steps of this problem to you. You will see that the total number of lost electrons is 2E - * 24 * 0.05mol = 2.4mole - the total number of lost electrons is 2E - * 24 * 0.05mol = 2.4mole - the total number of lost electrons is Cr: + 6 → x (6-x) e - * 20 * 0.02 * 2mol (special

How to calculate the electron transfer in redox reaction in senior one chemistry compulsory course?

The amount of electrons transferred by the substance is the amount of the substance multiplied by the amount of the substance. The electrons transferred in the whole reaction depend on the number of electrons transferred by the oxidant or reductant