5.6g of pure iron completely reacts with 100g of dilute hydrochloric acid. Find 1 the mass of hydrogen generated; The mass fraction of solute in this hydrochloric acid solution emergency

5.6g of pure iron completely reacts with 100g of dilute hydrochloric acid. Find 1 the mass of hydrogen generated; The mass fraction of solute in this hydrochloric acid solution emergency

Fe+2HCl=FeCl2+H2
56 73 2
5.6g x y
56/5.6g=73/x=2/y
x=7.3g y=0.2g
1. Mass of generated hydrogen 2G;
2 the mass fraction of solute in this hydrochloric acid solution is 7.3g/100g * 100% = 7.3%

Add 200ml of dilute sulfuric acid to the mixture of 54.4g iron powder and iron oxide, and the reaction is just complete. Release 4.48l of hydrogen (standard condition) reaction solution

(1) let the amount of iron substance that generates hydrogen after the reaction be x; The mass of iron oxide and iron in the centrifugation reaction are y, z.n (H2) = V / VM = 4.48l ÷ 22.4l / mol = 0.2molfe + H2SO4 = FeSO4 + H2 ↑ 1 1x 0.2mol2) Fe2O3 + 3h2so4 = Fe2 (SO4) 3 + 3H2O Fe + H2SO4 = FeSO4 + H2

Put 10g of iron powder containing impurities into 100g of dilute hydrochloric acid, and filter after reaction to obtain 105.4g filtrate. Calculate the mass fraction of iron in the iron powder Impurities do not react with dilute hydrochloric acid

Fe + 2HCl = FeCl2 + H2 ↑ 56 2 x 105.4-100 = 5.4G 56 / x = 54 / 5.4G △ M = 56-2 = 54 x = 5.6 mass fraction of iron: 5.6g/10g × 100％ ＝56...

100 g of dilute hydrochloric acid is reacted with sufficient iron powder to generate 0.4 g of hydrogen, and the mass of consumed iron powder is calculated

The concentration of 100g dilute hydrochloric acid is unknown, so the data of 100g can not be used directly. However, 0.4g hydrogen can be used
2HCl+Fe→FeCl2+H2↑
56 2
----=---- X=11.2g
X 0.4
Therefore, the mass of consumed iron powder is 11.2g

100g of a dilute hydrochloric acid reacts with a certain mass of iron powder to produce 0.4g of hydrogen. Calculate the mass of consumed iron powder

Let the mass of consumed iron be x G
Fe + 2Hcl = Fecl2 + H2↑
56 2
X 0.4g
X=11.2g
Answer: the mass of consumed iron is 11.2g

one hundred   G dilute hydrochloric acid 100   g   Complete reaction of 16% sodium hydroxide solution, find: (1) Mass of sodium chloride produced: (2) Mass fraction of solute in dilute hydrochloric acid

Let the mass of HCl participating in the reaction be x, and the mass of sodium chloride generated be yhcl + NaOH ＾ NaCl + h2o36.5    forty      58.5x     100g × 16%   y36.5x＝40100g × 16%   x=14.6g40100g × 16%＝58.5y   y=2...