## What is meant by a sucrose solution with a mass fraction of 80g solute of 5%

The solute is sucrose. After sucrose is dissolved in water, this cup is called sucrose solution

80g * 5% = 4G sucrose. A total of 4G sucrose is dissolved in this glass of water

### 13g zinc reacts completely with 100g dilute sulfuric acid (1) the mass of dilute sulfuric acid solvent and solute (2) the mass of solute and solvent of the resulting solution

Zn+H2SO4=ZnSO4+H2

65 98 161

13g x y

65/13g=98/x=161/y

x=19.6g y=32.2g

(1) Dilute sulfuric acid solvent 100g-19.6g = 80.4g, mass of solute 19.6g

(2) The solute of the obtained solution is 32.2g, and the solvent mass is 80.4g

### 13g zinc reacts with 100g dilute sulfuric acid to obtain 1) Quality of solute and solvent in dilute sulfuric acid 2) The solute in the obtained solution, the mass of the solution

Zn+H2SO4=ZnSO4+H2↑

65...98.161.2

13--x-----y----z

x=19.8

y=26.2

z=0.4

Before reaction

M (solute) = 19.8g

M (solvent) = 100-19.8 = 80.2g

After reaction

M (solute) = 26.2g

M (solution) = 100 + 13-0.4 = 112.6g

### Put 6.5g zinc particles into 100g dilute sulfuric acid and the reaction is just complete. Try to calculate the mass of the solution and its solute after the reaction

Zn + H2SO4 === ZnSO4 + H2↑

65 161 2

6.5g x y

65/6.5g=161/x=2/y

x=16.1g

y=0.2g

The mass of the obtained solution is 6.5g + 100g-0.2g = 106.3g

The mass of solute in the obtained solution is 16.1g

### Xiaohua reacted with 6.5g zinc particles and 100g dilute sulfuric acid Xiaohua used 6.5g zinc particles and 100g dilute sulfuric acid to exactly complete the reaction to calculate: 1. Quality of hydrogen produced by reaction The mass of the solution and the mass of the solvent obtained after the reaction 3. Mass of solute in dilute sulfuric acid Can you speak and write in detail~~~ 2. How to get the quality of the solvent inside?? And the answer to the third question should be more detailed?

Zn+H2SO4=H2+ZnSO4

65 98 2 161

It can be seen that excess zinc sulfate can react completely

Therefore, the mass of hydrogen is 0.2g

The difference method showed that the solution lost 0.2g, obtained 6.5g, and the mass increased by 6.3g to 106.3g

### It is known that the mass fraction of nitrogen in the solid mixture of NH4NO3 and KH2PO4 is 28%, so the mass fraction of KH2PO4 in the mixture is () A. 20% B. 25% C. 85% D. 80%

If the mass of the mixture is m, then the mass of NH4NO3 is X. according to the fact that the mass of N element in NH4NO3 is equal to the mass of N element in the mixture,

Then M × 28%═X × fourteen × two

fourteen × 2+1 × 4+16 × three × 100%

Solution x

M═0.8

Then the mass fraction of NH4NO3 in the mixture is X

M × 100%═80%，

The mass fraction of KH2PO4 is 1-80% - 20%,

So choose a