A factory needs to use dilute sulfuric acid with solute mass fraction of 28% to remove rust for metal. The purchaser bought 2000ml98% concentrated sulfuric acid (density: 1.84g/cm3) from the chemical plant. How many kilograms of 28% dilute sulfuric acid can the worker master dilute it? How many liters of water do you need? My answer is: 2000mL × 1.84g/cm3 × 98%=3.6064kg 3606.4g÷(28% × 1g/cm3)=12.88L But the correct answer is: 12.88kg 9.2L

A factory needs to use dilute sulfuric acid with solute mass fraction of 28% to remove rust for metal. The purchaser bought 2000ml98% concentrated sulfuric acid (density: 1.84g/cm3) from the chemical plant. How many kilograms of 28% dilute sulfuric acid can the worker master dilute it? How many liters of water do you need? My answer is: 2000mL × 1.84g/cm3 × 98%=3.6064kg 3606.4g÷(28% × 1g/cm3)=12.88L But the correct answer is: 12.88kg 9.2L

Your thinking (the mass of solute in concentrated sulfuric acid and dilute sulfuric acid is equal) is right, but you made a mistake in step 2. Step 1: 2000ml × 1.84g/cm3 × 98% = 3.6064kg is the mass of solute. Step 2: 3.6064kg ÷ 28% = 12.88kg is the mass of dilute solution. Step 3: add water to the concentrated solution to become