 # How many grams of water need to be evaporated to concentrate 100g of sucrose solution with 10% mass fraction into 20% sucrose solution

## How many grams of water need to be evaporated to concentrate 100g of sucrose solution with 10% mass fraction into 20% sucrose solution

100*10%=(100-x)20%
x=50

### There are 100 grams of 10% KNO3 solution, and the method to increase the solute mass fraction to 20% is () A evaporate 50 g of water B add 100 g of 10% KNO3 solution C decreases to a certain temperature D increases 10 g KNO3 solid The answer is a, for detailed reasons~~

100g*10%/(20%)=50g
Therefore, it is only necessary to heat and evaporate the original solution to a total mass of 50g

### In a potassium nitrate solution with a mass fraction of 20% of 50g solute: (1) add 10g potassium nitrate to completely dissolve; (2) Add 10g water; (3) After evaporation of 10G water, potassium nitrate did not precipitate from the solution. How would the solute mass fraction of potassium nitrate solution change? Calculate the answer

Your question is: how will the solute mass fraction of potassium nitrate solution change after adding solute, adding solvent and evaporating solvent to the original solution? In the potassium nitrate solution with the mass fraction of 50g solute of 20%, the mass of potassium nitrate = 50g * 20% = 10g (1) the mass fraction of solute of potassium nitrate solution = (10g + 10g) /

### There are enough sucrose solids, enough water, 80g solute mass fraction of 5% sucrose solution and 50g solute mass fraction of 20% sucrose solution in the laboratory. To prepare 100g solute mass fraction of 10% sucrose solution, please design three schemes: （1）______ （2）______ （3）______

(1) Prepare 100g solute mass fraction of 10% sucrose solution, sucrose required: 100g × 10% = 10g, water demand: 100g-10g = 90g;
(2) If 50g 20% sucrose solution is used to prepare: solute: 50g × 20% = 10g, water required: 100g-50g = 50g;
(3) If 80g 5% sucrose solution is used for preparation: solute: 80g × 5% = 4G solute required: 10g-4g = 6G water required: 100g-80g-6g = 14g
So the answer is: (1) 10g sucrose and 90g water; (2) 50 g of 20% sucrose solution and 50 g of water; (3) 80g 5% sucrose solution, 6G sucrose and 14g water

### What is the mass of sucrose to be added when the mass fraction of 100 g of 20% sucrose solution (1) solute increases to 40%? Brothers What is the mass of sucrose to be added when the mass fraction of 100 g of 20% sucrose solution (1) solute increases to 40%? The brothers gave a certain praise

Solution 1: suppose you need to add 100g sucrose a × 20% + a = (100g + a) × 40% a = 100 / 3 G ≈ 33.3 G A: the mass of sucrose to be added is 33.3 g. solution 2: the mass of solvent water in 100 g of 20% sucrose solution = 100 g × (1-20%) = quality of 80 g 40% sucrose solution

### When a g water is added to a G 30% sucrose solution, the mass fraction of solute in the solution is ()?

In a G 30% sucrose solution, sucrose has a * 30% = 0.3ag
Therefore, when a g water is added to a G 30% sucrose solution, the mass fraction of solute in the solution is
0.3a/(a+a)*100%=0.3/2 * 100%=15%