249.5 g of dilute sulfuric acid is added to a beaker containing 50 g of calcium carbonate and the reaction is just complete. Try to calculate the mass fraction of solute in the solution obtained after the reaction
Let the mass of generated calcium chloride be x and the mass of carbon dioxide be y
CaCO3+2HCl==CaCl2+H2O+CO2↑
100 111 44
50g X Y
100:111=50g:X
X=55.5g
100:44=50g:Y
Y=22g
Mass fraction of solution after reaction = 55.5g / (249.5g + 50g-22g) = 20%