If 5.6 g of iron powder is completely oxidized to Fe2O3 powder, the mass of oxygen consumed is _____, Its chemical equation is_________

If 5.6 g of iron powder is completely oxidized to Fe2O3 powder, the mass of oxygen consumed is _____, Its chemical equation is_________

4Fe+3O2====2Fe2O3
The relative atomic mass of iron is 56
The proportion of Fe2O3 is 112 divided by 160, so the mass of Fe2O3 is 8 G
Oxygen mass equals 8 minus 5.6 equals 2.4 grams