2x^2-4x+1=0,(x+1)(x+2)(x-3)(x-4)=?

2x^2-4x+1=0,(x+1)(x+2)(x-3)(x-4)=?

2x²-4x=-1
x²-2x=-1/2
Original formula = [(x + 1) (x-3)] [(x + 2) (x-4)]
=(x²-2x-3)(x²-2x-8)
=(-1/2-3)(-1/2-8)
=119/4

Elden Ring Premiere

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