1 + 2-3-4 + 5 + 6-7-8 + 9 + 10-11-12. It is a continuous integer starting from 1. You can find the algebraic sum of 2008 numbers by taking two integers and two negatives in turn

1+2-3-4=-4
5+6-7-8=-4
...
A cycle of four
There are 502 cycles of 2008 / 4 in 2008
So the original formula = (- 4) * 502 = - 2008

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