As shown in the figure, AB is the diameter of ⊙ o, ab = 2, OC is the radius of ⊙ o, OC ⊥ AB, point D is on AC, ad = 2CD, point P is a moving point on radius OC, and the minimum value of AP + PD is obtained

As shown in the figure, AB is the diameter of ⊙ o, ab = 2, OC is the radius of ⊙ o, OC ⊥ AB, point D is on AC, ad = 2CD, point P is a moving point on radius OC, and the minimum value of AP + PD is obtained

As shown in the figure, connect BD and ad. it is known that B is the symmetry point of a with respect to OC, so BD is the minimum value of AP + PD, ∵ ad = 2CD, and the degree of arc AC is 90 ° arc, ∵ ad is 60 ° arc, so ∠ B = 30 °, ∵ AB is diameter, ∵ ADB = 90 ° and ab = 2, ∵ BD = 3. Therefore, the minimum value of AP + PD is 3