Factorization of 2x ^ 2-4xy + 2Y ^ 2-3 (X-Y + 3)

2x^2-4xy+2y^2-3(x-y+3)
=2（x²-2xy+y²）-3（x-y）-9
=2（x-y）²-3（x-y）-9
=[2（x-y）+3][（x-y）-3]

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