A bulb marked with "24 V 40 W" is connected to a 36 V power supply. In order to make it shine normally, what resistance should be connected in series? The power consumed by this resistance

The series current is the same, the current is 40W / 24V = 5 / 3a, Ohm's law is r = u / I = 24 / (5 / 3) = 72 / 5ohm, R total = 36 / (5 / 3) = 108 / 5ohm, R parallel = 36 / 5ohm, P = ixixrxr = (5 / 3) x (5 / 3) x (36 / 5) = 20W

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