There are three cars, a, B and C, each driving from a to B at a certain speed. B starts 10 minutes later than C, and after 40 minutes it catches up with C. A starts 20 minutes later than B, and after 50 minutes it catches up with B______ How many minutes to catch up with C?

[(20 + 50) × 50] × [(40 + 10) × 40], = [70 ／ 50] × [50 ／ 40], = 75 × 54, = 1.75 (Times); (10 + 20) × 1.75-1, = 40 (minutes). A: after 40 minutes, a catches up with C. so the answer is 40

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