The total age of Xiaoming's parents is 82. His father is 2 years older than his mother. What's the age of his father? List the equality between quantities formulation of equation Complete plus reward

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• 1. Xiaoming is 9 years old, his father is 38 years old and his mother is 35 years old. A few years later, the sum of his parents' ages is seven times of Xiaoming's?
• 2. Xiaoming is 10 years old. The sum of his mother's and father's age is 71 years old. How many years later, their average age is 35 years old
• 3. This year, Xiaoming is 9 years old, his father is 38 years old, and his mother is 35 years old. A few years later, the sum of the ages of his parents is seven times that of Xiaoming
• 4. Xiao Ming is 8 years old. He is 81 years old with his parents______ Three years later, their average age was 34, when Xiao Ming______ I'm 40 years old
• 5. Xiaoming is ten years old. His mother and father are 71 years old. How many years later, their average age will be 35 years old?
• 6. My parents' love for me
• 7. Thank you, mom and dad
• 8. Mom and Dad, I want to tell you composition Sometimes we have different views from our parents, even misunderstanding. Just write one thing. I don't want to copy, I want to refer to how others write
• 9. Mom and Dad, I want to tell you
• 10. Mom and Dad, I want to tell you
• 11. Can you spell it in English?
• 12. Suppose the bonus tax rate is as follows (a for bonus, R for tax rate) a
• 13. It costs 6.8 yuan to buy 1000 kg of apples and 3000 kg of grapes. It is known that 1000 kg of apples is twice as much as 2000 kg of grapes. It costs 0.3 yuan. How much is 500 g of apples
• 14. The sum of all the numbers in the sequence 1,2,3,... 10000? The answer is 180001
• 15. General term of sequence A1 = 2, an = [a (n-1) + 1] * [10000 + 10000a (n-1)] / [10000 + 10000a (n-2] to find the general term formula, this, should not be solved... No way to start
• 16. Find a general formula of the following sequence 5.50.500.5000
• 17. General term formula of sequence 5,505005000
• 18. How to use VB to generate 10000 numbers of 1 ~ 10000 randomly, and classify them according to 1 ~ 1000, 1001 ~ 2000, 2001 ~ 3000, 9001 ~ 10000? How to use VB to generate 10000 numbers from 1 to 10000 randomly, and classify them according to 1 ~ 1000, 1001 ~ 2000, 2001 ~ 3000.9001 ~ 10000? Write like this Private Sub Command1_ Click() Cls Dim a(100) Dim n(10) Dim s(10) For i = 1 To 100 a(i) = Int(Rnd() * 100) k = Int(a(i) / 10) + 1 n(k) = n(k) + 1 s(k) = s(k) + a(i) Next For i = 1 To 10 Print n(i), Next Print For i = 1 To 10 Print s(i), Next Print For i = 1 To 10 Print s(i) / n(k), Next Print Print For i = 1 To 100 Print a(i), If i Mod 10 = 0 Then Print End If Next Print Print k,s(k),n(k) End Sub I just found out
• 19. When x = 1,10100100010000, what are the values of 2x-10 / X and what do you find? If you know how to describe this rule, it's mainly about discovery. I hope some professionals can explain it, It's (2x-10) / X
• 20. If the bank interest rate is 12%, in order to get 10000 yuan after five years, how much should be deposited in the bank now? Assuming compound interest