If x + y = 5 is known, then x + y + 6 = 5 + 6 = 11; if x + y + 6 = 15 is known, then x + y = 9. In the above operations, the whole idea is reflected, and here x + y can be used As a whole Given that the square of 2x + 3x = 5, then the square of 2x + 3x + 1= (2) Given that the square of x-2x-5 = 0, then the square of 2x-4x-5= (3) Given a + B = 3, ab = - 2, find the value of - 2 (a + AB) + (ab-2b) + 1

If x + y = 5 is known, then x + y + 6 = 5 + 6 = 11; if x + y + 6 = 15 is known, then x + y = 9. In the above operations, the whole idea is reflected, and here x + y can be used As a whole Given that the square of 2x + 3x = 5, then the square of 2x + 3x + 1= (2) Given that the square of x-2x-5 = 0, then the square of 2x-4x-5= (3) Given a + B = 3, ab = - 2, find the value of - 2 (a + AB) + (ab-2b) + 1

① Take 2x & # 178; + 3x as a whole, 2x & # 178; + 3x + 1 = 5 + 1 = 6. ② take X & # 178; - 2x as a whole, the original formula X & # 178; - 2x = 5, then 2x & # 178; - 4x-5 = 2 (X & # 178; - 2x) - 5 = 2 × 5-5 = 5, ③ - 2 (a + AB) + (ab-2b) + 1 is reduced = - 2a-2ab + ab-2b + 1 = - 2 (a + b) - AB + 1 is substituted into known