(b-c)(b+c-a)+(c-a)(c+a-b)+(a-b)(a+b-c) It is related to factorization

(b-c)(b+c-a)+(c-a)(c+a-b)+(a-b)(a+b-c)
=b^2-c^2-a(b-c)+c^2-a^2-b(c-a)+a^2-b^2-c(a-b)
=0

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