Two practical questions, please answer as soon as possible, thank you 1. A car can save 1.8 liters of gasoline by driving 200 kilometers. According to this calculation, how many liters of gasoline can be saved by driving 1500 kilometers? (using the proportional solution) (the process of solving the equation to be set) 2. The two passenger and freight cars leave each other from the two places. After meeting, the two cars continue to arrive at each other's terminal. They return immediately and meet again on the way. The two meeting places are 3000 meters apart. It is known that the speed of the freight car is two-thirds of the speed of the passenger car. How many meters is the distance between the two places

Two practical questions, please answer as soon as possible, thank you 1. A car can save 1.8 liters of gasoline by driving 200 kilometers. According to this calculation, how many liters of gasoline can be saved by driving 1500 kilometers? (using the proportional solution) (the process of solving the equation to be set) 2. The two passenger and freight cars leave each other from the two places. After meeting, the two cars continue to arrive at each other's terminal. They return immediately and meet again on the way. The two meeting places are 3000 meters apart. It is known that the speed of the freight car is two-thirds of the speed of the passenger car. How many meters is the distance between the two places

1. It can save x liters
200/1.8=1500/x
x=1500*1.8/200=13.5
two