As shown in Figure 7, the right angle centers of two triangular plates are superposed together. (1) if the superposed angle BOC = n degrees (0 is smaller than n is smaller than 90), then the complement degree of angle AOD
(1) If the ratio of degree between ∠ DOB and ∠ doa is 2:11, the degree of ∠ BOC can be calculated; if ∠ DOB = 2x, then: ∠ DOA = 11x and ∠ DOA = ∠ DOB + ∠ AOB = 2x + 90 ° so: 11x = 2x + 90 ° so: x = 10 ° and ∠ BOC = 90 ° - DOB = 90 ° - 2x