As shown in Figure 7, the right angle centers of two triangular plates are superposed together. (1) if the superposed angle BOC = n degrees (0 is smaller than n is smaller than 90), then the complement degree of angle AOD

As shown in Figure 7, the right angle centers of two triangular plates are superposed together. (1) if the superposed angle BOC = n degrees (0 is smaller than n is smaller than 90), then the complement degree of angle AOD

(1) If the ratio of degree between ∠ DOB and ∠ doa is 2:11, the degree of ∠ BOC can be calculated; if ∠ DOB = 2x, then: ∠ DOA = 11x and ∠ DOA = ∠ DOB + ∠ AOB = 2x + 90 ° so: 11x = 2x + 90 ° so: x = 10 ° and ∠ BOC = 90 ° - DOB = 90 ° - 2x