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-6, - 0.15,4 / 9100,4 and 1 / 2,0,58,5.3 cycles, - 1 / 7,2 and 3 / 8 which are positive fractions and which are non negative integers
Positive: 4 / 9.4 and 2 / 1.2 and 3 / 8 negative: 100.0.58
RELATED INFORMATIONS
- 1. 58/0.26=
- 2. Simple calculation of (67 × 76 + 76 × 58) × 8 and 79 × 125
- 3. It can be easily calculated by simple method. 40 × 95 + 5 & nbsp; & nbsp; & nbsp; & nbsp; 102 × 58-116 & nbsp; & nbsp; & nbsp; & nbsp; 11 × 203-3 (200 + 3) × 14 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 125 + 4 × 95 & nbsp; & nbsp; & nbsp; & nbsp; (7 × 125) × 8
- 4. (67.8+9.48)÷0.96-2.58×3.35 ：(67.8+9.48)÷0.96－2.58×3.35 Simple operation
- 5. (-5\8)*（-3.58）-（5/8)*(-3.42)-(-5|8)*7 Within today
- 6. How to calculate (26 + 120-58) × 4 with a simple method?
- 7. (386 + 142) + (14 + 58) = calculated by simple method
- 8. Calculation of 999x58 + 558 by simple method
- 9. Answer to the second question on page 34 of mathematics exercise book (Volume 2, grade 6, Jiangsu Education Press)
- 10. Final examination of mathematics exercise book for Grade 6 Volume 2 of Jiangsu Education Press fast
- 11. There are 48 students in class 6 (2). The number of boys is three fifths of that of girls. How many boys and girls are there in class 6 (2)?
- 12. There are 48 students in a class, of which 5 / 6 are boys. How many are girls
- 13. There are 48 students in class 61 of Guangming primary school. Among them, there are 8 more girls than 3 / 5 of boys. There are several men and women in each class in six years
- 14. There are 84 people in class 5 (1) and class 5 (2), 5 / 8 of class 5 (1) and 3 / 4 of class 5 (2), with a total of 58 people. How many people are there in each class
- 15. 5. There are 84 students in class 1 and class 2. There are 58 students in 5 / 8 of class 1 and 3 / 4 of class 2? How many points are there for class 1 in 5 years more than Class 2 in 5 years, and how many points are there for class 2 in 5 years less than Class 1 in 5 years?
- 16. A. There are 84 students in class B and 58 students in 8 / 5 of class A and 4 / 3 of class B, so there are () students in class A There can only be one unknown number. Let a be x and B be (84 - x)
- 17. There are 84 people in class 61 and class 62, 5 / 8 of class 61 and 3 / 4 of class 62. How many people are there in class 61
- 18. There are two ways
- 19. Simple algorithm: 1.6 times 45%, 2 times 4.5%, 0.12 times 4.5
- 20. 5.2×58+52×4.