As shown in the figure, in the isosceles trapezoid ABCD, ad = 4cm, BC = 8cm, e is the midpoint of the waist AB, CE divides the trapezoid circumference into two parts, the difference is 3cm, and calculates the trapezoid circumference
∫ the quadrilateral ABCD is isosceles trapezoid, e is the midpoint of the waist AB, CE divides the trapezoid perimeter into two parts (AE + AD + CD) - (be + BC) = 3, or (be + BC) - (AE + AD + CD) = 3, ad = 4, BC = 8, ∫ 4 + CD-8 = 3, ∫ CD = 7, or 8-4-cd = 3, ∫ CD = 1 ∫ CD = AB = 7, or CD = AB = 1 ∫ the trapezoid perimeter
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- 1. As shown in the figure, in the isosceles trapezoid ABCD, ad = 4cm, BC = 8cm, e is the midpoint of the waist AB, CE divides the trapezoid circumference into two parts, the difference is 3cm, and calculates the trapezoid circumference
- 2. In the trapezoidal ABCD, ab = 8, ad = 5, CD = 6, BC = 15. Point E is on the bottom BC, and point F is on the waist CD. EF bisects the area and perimeter of ABCD at the same time to find the length of CE
- 3. In the isosceles trapezoid ABCD, AD / / BC, assuming BC = 4, ad = 8, angle a = 45 degrees, the area of the trapezoid is calculated
- 4. As shown in the figure, in the trapezoidal ABCD, ad ‖ BC, ∠ B = 90 °, ab = 14cm, ad = 18cm, BC = 21cm, point P starts from point a, moves at 1cm / s along side ad to point D, and point Q starts from point C, moves at 9cm / s along side CB to point B. If one point moves to the end point, the other point stops. If P and Q start at the same time, can a quadrilateral PQCD become an isosceles trapezoid? If so, how many seconds? If not, please give reasons
- 5. As shown in the figure, in the trapezoidal ABCD, ad ‖ BC, ∠ B = 90 °, ab = 4cm, ad = 18cm, BC = 21cm, point P starts from point a, moves 2cm / s along edge ad to point D, point Q starts from point C, moves 6cm / s along edge CB to point B, P and Q start at the same time, if one point moves to the end point, the other point stops=______ Cm; 2______ Second, PQ = CD
- 6. Let AB = a, ad = B, BC = 2B (a > b). Make de ⊥ DC, de intersect AB at point E, connect EC. (1) try to judge whether △ DCE and △ ade, △ DCE and △ BCE are similar. (2) for the above judgment, if the two triangles must be similar, please prove it. (3) if not, please point out when a and B satisfy what relationship, they can be similar?
- 7. As shown in the figure, in ladder ABCD, ad ∥ BC, ∠ C = 90 ° and ab = ad. connect BD, make a vertical line of BD through point a, intersect BC at point E, and the vertical foot is h. if EC = 3cm, CD = 4cm, calculate the area of ladder ABCD
- 8. In isosceles trapezoid ABCD, ad is parallel to BC, ab = CD, P is a point on BC, PE is parallel to CD, AC intersects with E, PF is parallel to AB, BD intersects with F
- 9. P is any point on the side BC of the square ABCD, and PE is perpendicular to BD intersecting BDE, PF is perpendicular to AC intersecting AC, if AC = 10, EP = FP
- 10. In trapezoidal ABCD, CD is equal to AB, if angle a = 45 degrees, angle B = 60 degrees, BC = 5, find the length of AD and ab
- 11. As shown in the figure, in the isosceles trapezoid ABCD, ad = 4cm, BC = 8cm, e is the midpoint of the waist AB, CE divides the trapezoid circumference into two parts, the difference is 3cm, and calculates the trapezoid circumference
- 12. As shown in the figure, in the isosceles trapezoid ABCD, ad = 4cm, BC = 8cm, e is the midpoint of the waist AB, CE divides the trapezoid circumference into two parts, the difference is 3cm, and calculates the trapezoid circumference
- 13. E is on CD, f is a point on the extension line of BC, CE = CF (1) proves that triangle BCE congruent triangle DCF (2) ∠ FD E is on CD, f is a point on BC extension line, CE = CF (1) Proof of triangle BCE congruent triangle DCF (2) How much is ∠ FDC = 30 ° and ∠ bef = 0
- 14. As shown in the figure, in square ABCD, e is a point on CD, f is a point on BC extension line, CE = cf. (1) prove: △ BCE ≌ △ DCF; (2) if ∠ BEC = 60 °, calculate the degree of ∠ EFD
- 15. As shown in the figure, in square ABCD, e is a point on the edge of CD, f is a point on the extension line of BC, CE = CF
- 16. As shown in the figure, in the square ABCD, f is a point on CD, AE ⊥ AF, point E is on the extension line of CB, EF intersects AB at point G, proving: de · FC = BG · EC
- 17. As shown in the figure, the point E is on the diagonal BD of the square ABCD, and be = AB, EF ⊥ BD, EF and CD intersect at the point F to prove de = EF = FC
- 18. As shown in the figure, in square ABCD, e is a point on the edge of BD, and be = BC, EF is perpendicular to BD, intersecting CD with F
- 19. As shown in the figure, take a point E on the diagonal BD of square ABCD, make be = BC, make ef vertical BD, intersect CD with F. the line segment De is equal to EF and FC? Why?
- 20. How to calculate the electricity consumption of refrigerator in an hour What is the formula?