The ratio of walking speed between a and B is 7:5. They set out from a and B at the same time and walk in opposite directions. They met at 0.5 hours The walking speed ratio of a and B is 7:5. They start from a and B at the same time and walk in opposite directions. They meet after 0.5 hours. If they start from a and B at the same time and walk in the same direction (one is in a and the other is in B, but they all face the same direction), how many hours will it take a to catch up with B? There must be process and reason No equations

1. Suppose that a's walking speed is x km / h. because the ratio of the walking speed of a and B is 7:5, B's walking speed is 5 / 7X km / h. therefore, the distance between a and B (that is, the distance difference between a and B in the same direction) is: (x + 5 / 7X) 0.5 = 6 / 7X. The time that a needs to catch up with B is t hour, so a and B need to walk

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