The side is a 10 cm cube with a gravity of 100 n. put it in the center of the table with a side length of 50 cm The force of 20n is the pressure on the table at this time
Answer: 8000pa
Analysis:
The pressure of the object on the table is: F = G-F pull = 100-20 = 80N
Stress area: S = 10 × 10 = 100cm2 = 0.01m2
The pressure is: P = f / S = 80 / 0.01 = 8000pa
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