If a rectangle whose length is 1cm more than its width is equal to the perimeter of a square whose side length is a cm, the length of the rectangle is (). A 2a-1 / 2 B 2A + 1 / 2
The answer is a
Let the width of the rectangle be B, then the length be (B + 1), and the perimeter be (B + 1 + b) * 2
The perimeter of a square is 4a
If the perimeter of the two is equal, (B + 1 + b) * 2 = 4A, then (B + 1) = 2a-1 / 2, and the answer is a
Don't know how to ask ~ ~ please accept~~
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