For a division with remainder, the quotient is 14 and the remainder is 6. Given that the sum of the divisor and the divisor is 126, what are the divisor and the divisor respectively?
Divisor = 14 * divisor + 6
Divisor = (126-6) / (14 + 1) = 8
Divisor = 8 * 14 = 112
RELATED INFORMATIONS
- 1. The general solution to the x power of the differential equation y "+ 3Y + 2Y = e
- 2. Calculate (5 × (36) + 15 × (8) + 5 × (4 × (25) × 9 (50) Fast, fast
- 3. 1. (- 2x-1) (3x-2) 2.2x (x-3) (1 / 2x + 2) 3. (a + 3) (A-1) + a (A-2) 4. (a square + 3) (A-2) - A (a square-2a-2)
- 4. How much is 1 / 3 plus 1 / 15 plus 1 / 35 plus 1 / 63 plus 1 / 99
- 5. 1-3n=-8 0.2x+12=0.3x+9 1/2x+1=1/3x-5
- 6. 666 * 778 + 333 * 444 (ingenious calculation)
- 7. If 3x3-x = 1, then the value of 9x4 + 12x3-3x2-7x + 1999 is equal to () A. 1997B. 1999C. 2001D. 2003
- 8. Simple operation of 1 / 2 × 11 / 20 + 1 / 2 × 20 / 49
- 9. 1. If a > b, E > F, C > 0, then F-AC < e-bc
- 10. 2 meters = how many decimeters
- 11. Given the function f (x) = x2 + ax + 3, when x ∈ [- 2,2], f (x) ≥ A is constant and the range of a is obtained Can we use the method of variable separation?
- 12. What is 3 plus 5 divided by 2 times 4?
- 13. (a + b) 2 power * (B + a) 3 power fast
- 14. How to round? Take a few examples to see if 3561 is about 3600 or 4000 Give a few more examples and concepts
- 15. The function y = sin ^ 2 x-cosx + 3, X belongs to (2 π / 3, π / 6] and the range is
- 16. As shown in the figure, the side length of square ABCD is 2, point E is the midpoint of BC side, BG ⊥ AE is made through point B, the perpendicular foot is g, extend BG to intersect AC at point F, then CF=______ .
- 17. As shown in the figure, e is a point on the edge BC of rectangle ABCD, EF ⊥ AE, EF intersects AC respectively, CD intersects at points m, F, BG ⊥ AC, perpendicular foot is C, BG intersects AE at point h. (1) (1) Verification: △ Abe ∽ ECF; (2) Find the triangle similar to △ ABH and prove it; (3) If e is the midpoint of BC, BC = 2Ab, ab = 2, find the length of EM. BG ⊥ AC, perpendicular to g, wrong number How to solve without trigonometric function
- 18. As shown in the figure, e is a point on the edge BC of rectangle ABCD, EF ⊥ AE, EF intersects AC respectively, CD intersects at points m, F, BG ⊥ AC, perpendicular foot is C, BG intersects AE at point H (1) Verification: △ Abe ∽ ECF; (2) Find the triangle similar to △ ABH and prove it; (3) If e is the midpoint of BC, BC = 2Ab, ab = 2, find the length of EM BG ⊥ AC is g, wrong number
- 19. The side length of square ABCD is 2, AE = EB, Mn = 1, the two ends of line Mn are on BC and CD, if △ AED is similar to triangle with m, N and C as vertex Find the length of CM
- 20. Triangle AEC, AE = be, D and C are a point on AE and EB respectively and de = CE. Is quadrilateral ABCD isosceles trapezoid? Why?