The area of the overlapping part is equal to 1 / 4 of the small rectangle, 1 / 6 of the large rectangle, and the ratio of the small rectangle to the large rectangle

"Hy573700": Hello
Let the small rectangle be a, the large rectangle be B, and the overlapping part be c
c:a＝1:4,a＝4c
c:b＝1:6,b＝6c
a:b＝4:6＝2:3
A: the ratio of a small rectangle to a large rectangle is 2 to 3
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