In trapezoidal ABCD, ad: BC = 2:3, the area of triangle AOB is 6 square centimeters, and what is the area of trapezoidal ABCD A D O B C
AOB area is equal to cod area,
AOB area: AOD area = Bo: do = BC: ad = 3:2,
AOB area: BOC area = Ao: CO = ad: BC = 2:3,
So the area of ABCD is 6 + 6 + 4 + 9 = 25
RELATED INFORMATIONS
- 1. As shown in the figure, the square ABCD and an isosceles right triangle EFG (EF = EG) are placed on the same straight line. Now the triangle does not move, and the square moves to the right at a speed of 2 cm / s along the straight line at a constant speed? (1) At 10 seconds______ (2) in the 11th second______ (3) at the 13th second______ Square centimeter; 4______ Second, the area of the overlap is 18 square centimeters______ Second, the area of the overlap is 34 square centimeters
- 2. As shown in the figure, the square ABCD and an isosceles right triangle EFG (EF = EG) are placed on the same straight line. Now the triangle does not move, and the square moves to the right at a speed of 2 cm / s along the straight line at a constant speed? (1) At 10 seconds______ (2) in the 11th second______ (3) at the 13th second______ Square centimeter; 4______ Second, the area of the overlap is 18 square centimeters______ Second, the area of the overlap is 34 square centimeters
- 3. How to cut out four identical isosceles right triangles on the four corners of a 2cm square piece of paper ABCD, Finding the side length of a regular octagon
- 4. As shown in the figure, in the square ABCD with side length of 12 cm, the isosceles triangle PAB with waist length of 10 cm is made with ab as the bottom edge. Then the area of the triangle PAC is equal to______ Square centimeter
- 5. In the pyramid v-abcd, if the bottom surface ABCD is a square with side length 2 and the other four sides are isosceles triangles with waist length 5, then the dihedral angle v-ab-c The size of the plane angle is——
- 6. As shown in the figure, in the isosceles triangle ABCD, AB is parallel to CD, AC = 10 cm, CE is perpendicular to AB, e, CE = 6, find the area of trapezoid ABCD
- 7. As shown in the figure, the side length of square ABCD is 2, and △ BCE is an equilateral triangle. Complete the figure and find the area of △ ade The picture is a square
- 8. As shown in the figure, e is a point in the square ABCD. If △ Abe is an equilateral triangle, then ∠ BCE=
- 9. As shown in the figure, AB is parallel to Cd in ladder ABCD. If AB = CD, is ladder ABCD isosceles triangle? Why?
- 10. As shown in the figure, e is the point on the diagonal BD of the square ABCD with side length 1, be = BC, P is any point on CE, PQ ⊥ BC is at point Q, PR ⊥ be is at point R, then the value of PQ + PR is () A. 22B. 12C. 32D. 23
- 11. A trapezoid, ad: BC (ratio of top to bottom) is 2:3, the area of triangle ABO is 6 square centimeters, find the area of trapezoid ABCD The intersection of AC and BD is o
- 12. In trapezoidal ABCD, ad ‖ BC, ab = 8, ad = 5, CD = 7, ∠ B = 60 °, find the median line and its area of trapezoidal ABCD
- 13. If ad is parallel to BC, the median EF is 8 and the high ah is 10, the area of ladder shaped ABCD is 0
- 14. (1) In the rectangular trapezoid ABCD, ad is parallel to BC, ∠ a = 90 ° and ∠ d = 120 °, if ad is 1:2 to BC, the median length of the reminder is 9, then the trapezoid area is? (2) quadrilateral ABCD, e is the key point, f is a point on BC, and △ AEF is all equal to △ ABF, if CD = 12, then EF =? (3) rectangular ABCD, ab = 3, BC = 4, if the diagonal BD of the awakened eye is folded, then the area of △ EBD is? Write the answer directly,
- 15. AB two parallelograms are overlapped. The area of the overlapped part is one fourth of a and one sixth of B. It is known that the area of a is 12 square centimeters, so we can find the area of B
- 16. As shown in the figure, two parallelograms A and B are overlapped. The area of the overlapped part is 14 of a and 16 of B. It is known that the area of a is 12 square centimeters. Then the area of B is more than that of A______ Square centimeter
- 17. As shown in the figure, two rectangles A and B are overlapped. The area of the overlapped part is one third of a and one fifth of B. the known area of B is 60 square meters M, find the area of A
- 18. As shown in the figure, two rectangles AB are overlapped. The area of the overlapped part is 1 / 6 of a and 1 / 8 of B. It is known that the area of a is 12 square centimeters. Find the area of B Use the knowledge of solution proportion to solve, don't calculate formula ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~!!!!!!!!!!!!!!!!!!!!
- 19. As shown in the figure, two rectangles A and B are overlapped. The area of the overlapped part is one-third of a and one-fifth of B. the known area of B is 60 square centimeters What's the area of a in square centimeters
- 20. As shown in the figure, two rectangles A and B are overlapped together. The area of the overlapped part is one third of a and one fifth of B. the known area of B is 60 square centimeters. Find the area of A