Find the range of y = (2x ^ 2 = 4x-7) \ (x ^ 2 + 2x + 3)

Find the range of y = (2x ^ 2 = 4x-7) \ (x ^ 2 + 2x + 3)

y=(2x^2+4x-7)/(x^2+2x+3)
x^2y+2yx+3y=2x^2+4x-7
(y-2)x^2+2(y-2)x+3y+7=0
If the equation about X has a solution, the discriminant is greater than or equal to 0
So 4 (Y-2) ^ 2-4 (Y-2) (3Y + 7) > = 0
(y-2)(y-2-3y-7)>=0
(y-2)(2y+9)