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Why is the derivative of y = ln (2x-1) y '= 2 / (2x-1) = 2 How can I not understand Why is the derivative of y = ln (2x-1) y '= 2 / (2x-1) Sorry, I have the wrong number. There is no = 2 at the back
Derivative of Y '= 1 / (2x-1) * (2x-1) = 2 / (2x-1)
Don't think about it. Derivative is not equal to 2. Y '= 2 / (2x-1) is right
Supplement: This is the derivative of compound function, and the derivative of (2x-1) is 2,
Derivative of Y '= 1 / (2x-1) * (2x-1)
=2/(2x-1)
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