In the triangle ABC, BC = a, AC = C, and a = 45 degrees, C = 30 degrees, C = 10cm, find a, B and B!

B=180-A-C=105°
a/sinA=b/sinB=c/sinC
a/sin45=b/sin105=10/sin30
a=10/sin30*sin45=10√2
b=10/sin30*sin105=20*(sin60cos45+cos60sin45)=5(√6+√2)

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