Definite integral of 3 / 2 of function (square of 1-x) In the interval 0 to 1

∫(1-x^2)dx
=x-1/3(x^3)| 3/2
=[3-1/3*(3^3)]-[2-1/3*(2^3)]
=(3-3)-(2-8/3)
=2/3

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