Given the curve C: y = x ^ 3 + 2 and point P (1,3), then the tangent equation passing through point P and tangent to curve C is

Given the curve C: y = x ^ 3 + 2 and point P (1,3), then the tangent equation passing through point P and tangent to curve C is

. to find the derivative, let the intersection point be (x, x ^ 3 + 2), and use the equal slope to find the X of the intersection point;