Finding the derivative of y = LNX / (x ^ 2 + 1)

Finding the derivative of y = LNX / (x ^ 2 + 1)

y=lnx/(x²+1)
y`=[1/x(x²+1)-lnx(2x)]/(x²+1)²
=(x²+1-2x²lnx)/[x(x²+1)²]