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It is known that the second power of X is equal to five, the square of the third power of negative two x minus three times (the third power of negative four x n)
X2N = 5 (- 2x3n) 2 – 3 × (- 4xN) 3 = 4x3n × 2 – 3 × (- 4xN × 3) = 4x2n × 3 – 3 × (- 43x2n × 3 / 2) = 4 (X2N) 3 & nbsp; + 3 × 43 (X2N) 3 / 2 substitute X2N = 5 into the above formula: 4 × 53 & nbsp; + 3 × 43 × 53 / 2 = 4 × 125 + 3 × 64 × 5 × 51 / 2 = 600 + 960 × 51 / 2
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