X squared + 3x + a = 0 2, followed by X1 and X2, X1 squared - x2 squared = 3 for a X square + 3x + a = 0, 2 roots are X1 and X2 to find X1 square - x2 square = 3 to find a respectively

X squared + 3x + a = 0 2, followed by X1 and X2, X1 squared - x2 squared = 3 for a X square + 3x + a = 0, 2 roots are X1 and X2 to find X1 square - x2 square = 3 to find a respectively

x^2+3x+a=0,
It can be known from Veda's theorem
x1+x2=-3
x1x2=a
So X1 ^ 2-x2 ^ 2 = (x1 + x2) (x1-x2) = - 3 (x1-x2) = 3
So x1-x2 = - 1
So we can calculate X1 = - 2, X2 = - 1
So x1x2 = a = 2

Elden Ring Premiere

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