The domain of surface integral (x ^ 2 + y ^ 2) DS is bounded by z = x ^ 2 + y ^ 2 and z = 1 The answer is (5 radical 5 + 6) / 12 seeking process or seeking correct answer (the answer may be wrong)

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• 1. Let the tangent plane of the point (x, y, z) on the surface ∑: x ^ 2 / A ^ 2 + y ^ 2 / b ^ 2 + Z ^ 2 / C ^ 2 = 1 be π, and calculate the surface integral ∫ ∫ ∑ 1 / λ DS, where λ is the distance from the coordinate origin to π
• 2. Using Gauss formula, we can find the surface fraction ∮ XY ^ 2dydz + YZ ^ 2dzdx + ZX ^ 2dxdy, where ∑ is the outside of the sphere x ^ 2 + y ^ 2 + Z ^ 2 = R ^ 2 The reference answer is 4 π R ^ 5 / 5. But I'm always 2 π R ^ 5 / 5 My score is settled on the spot. My adoption rate is 100% Let P = XY & # 178;, q = YZ & # 178;, r = ZX & # 178; ∵αP/αx=y²,αQ/αy=z²,αR/αz=x² The original formula = ∫ ∫ (α P / α x + α Q / α y + α R / α z) dxdydz is obtained from Gauss formula =∫∫∫(x²+y²+z²)dxdydz =∫dθ∫sinφdφ∫r^4dr =(2π)[0--(1)](R^5/5-0) =2πR^5/5
• 3. Surface integral ∫ ∫ xdydz + Z ^ 2dxdy / (x ^ 2 + y ^ 2 + Z ^ 2), where surface ∑ is surrounded by x ^ 2 + y ^ 2 = R ^ 2 and z = R, z = - R
• 4. The surface integral ∫ (y ^ 2-x) dydz + (Z ^ 2-y) dzdx + (x ^ 2-z) DXDY, ∑ is Z = 1-x ^ 2-y ^ 2, which is located on the upper side above the side
• 5. ∫ (x ^ 2-y ^ 2) dydz + (y ^ 2-z ^ 2) dzdx + (Z ^ 2-x ^ 2) DXDY how to use Gauss formula? S is the upper half ellipsoid x ^ 2 / A ^ 2 + y ^ 2 / b ^ 2 + Z ^ 2 = 1 (z > = 0), take the upper side, and the Gauss formula is ∫ ∫ (x + y + Z) DV, which will not be done later
• 6. The surface integral ∫ ∫ xdydz + y ^ 2dzdy + zdxdy, ∑ is the upper side of the triangle on the plane where x + y + Z = 1 is cut by the coordinate plane
• 7. Is it possible to cut a conic section with a plane
• 8. Use a plane to cut off a cylinder and a cone. The shape of the section is the same ()
• 9. The shape of the cross section of a plane passing through the apex of a cone may be
• 10. Use a plane to cut a cone and a sphere. What are the shapes of the cross sections?
• 11. In order to know the coordinates of the two points and the azimuth of the two points, find the azimuth of the third point (know the distance), and the intersection of the third point and the first two points, according to the architectural plane drawing It's mainly that we often get plane drawings for setting out. Many of them are not right angles, but oblique lines. How can we find his azimuth I just use the total station. I asked about the angle between point 1 and point 3 and the azimuth of point 1.2. I already know how to calculate the coordinates of point 3 (know the distance between point 1 and point 3). Do you understand?
• 12. The shape of a window of a building is shown in the figure. The upper part is a semicircle, and the lower part is two windows with the same shape, m in length and N in width Rectangle, calculating (1) Total length of window and window frame (2) When m = 50cm, n = 20cm, what are the area of the window and the total length of the window frame
• 13. How should doors and windows be represented in the floor plan?
• 14. Is y = x ^ 2 + x a power function? Why?
• 15. Ln (2 + 3x) is expanded into a power function of X
• 16. Y = 1 / (x ^ 2-3x + 2) expanded to power function
• 17. In MATLAB, y = 1 / (x ^ 2), at x = 0, how much does it take to expand into a fifth-order power series?
• 18. Matlab draws the power exponent curve y = exp (- (x-1482.1) ^ 2) / 3694500; how to draw the curve of this function? The definition field is arbitrary
• 19. Using MATLAB to draw a function image, such as y = X. ^ 2-4 * x + 5, how to find the coordinates of the maximum point on the image
• 20. Draw the function image of F (x) = | X-2 |