When n takes what value, the (n & # 178; + n-1) degree of y = (n & # 178; + 2n) x is an inverse scale function? In which quadrant is its image?
When n takes what value, the (n & # 178; + n-1) degree of y = (n & # 178; + 2n) x is an inverse scale function? In which quadrant is its image?
The image is in the second and fourth quadrant
RELATED INFORMATIONS
- 1. Given the inverse scale function y = (1 / 2 of m-2) x, the two branches of the image with the power of - 2 are in the second and fourth quadrant respectively, and the value of M is obtained
- 2. It is known that the image with the inverse scale function y = m / X passes through the point (- 2, - 3), and the image with the inverse scale function y = m / X is in the second and fourth quadrants, and the value of M is calculated
- 3. 1. Translate the straight line y = 3x-2 upward by 4 units to get the straight line () 2. Which quadrant does the image of the first-order function y = 5x-2 pass through?
- 4. How many quadrants does the image of linear function y = - 5x + 2 not pass through
- 5. How many quadrants does the image of a linear function y = 5x + 2 pass through
- 6. The quadrant that the graph of a linear function y = - 5x + 3 does not pass through is______ .
- 7. As shown in the figure, it is known that the quadrilateral ABCD is a parallelogram, BC = 2Ab. The coordinates of two points a and B are (- 1,0), (0,2), respectively, and the coordinates of two points c and D are on the image of inverse scale function y = KX (k < 0), then K is equal to___ .
- 8. As shown in the figure, it is known that the quadrilateral ABCD is a parallelogram, BC = 2Ab, the coordinates of a and B are (1,0) (0,2) C respectively, and two points of D are on the graph of inverse scale function y = K / X The coordinate of point a is (10)
- 9. Given that point a (1,3) is on the image of the function y = K (x > 0), the edge BC of rectangle ABCD is on the x-axis, and E is the midpoint of diagonal BD, The image of function y = K (x > 0) passes through two points a and E, and the abscissa of point E is m (1) Find the value of K (2) find the abscissa of point C (expressed by M) (3) when ∠ abd = 45 °, find the value of M It is required to have steps to solve the problem and clear thinking
- 10. It is known that point (1,3) is on the image of function y = KX (x > 0), the edge BC of rectangle ABCD is on the X axis, e is the midpoint of diagonal BD, the image of function y = KX (x > 0) passes through two points a and E, and the abscissa of point E is m. The following problems are solved: (1) find the value of K; (2) find the abscissa of point C; (3) find the value of m when ∠ abd = 45 °
- 11. If the inverse scale function y = (k-1) x ^ k & # 178; - 5 passes through two or four quadrants, then k =?
- 12. Given that the image of a function y = 2mx + (6-3m & # 178;) passes through the origin and the second and fourth quadrants, then M=______
- 13. It is known that the linear function y = (3m + 1) x + M_ 2 1 if the function image passes through the origin, 2 finds the value of M. 2 if the function image does not pass through the second quadrant, 2 finds the value of M
- 14. It is known that the image of inverse scale function y = K / X passes through (1 / 2,8), and the line y = - x + B should pass through the image of inverse scale function (4, m) to find their inverse scale function and the function expression of the line
- 15. It is known that the image of the first-order function y = MX + N and the inverse scale function y = (3N-M) / X intersects at the point (1 / 2,2), and the value of M, N and another intersection point are obtained
- 16. Write the inverse proportional function of Y increasing with X in every quadrant of an image___ .
- 17. The image of inverse scale function y = 2 / X is in the fourth quadrant, in which y increases with the increase of X
- 18. Urgent! Let f (b) = B LNA - a LNB (b > a > e), then what is f '(b) equal to? Given that a and B are real numbers, and a > b > e, where e is the base of natural logarithm, we prove that a ^ b > b ^ a
- 19. Given a = 4 and B = 3, when vector A / / vector B, find the product of a and B
- 20. Vector a = (3,2) when x is, vector b = (x, 1) is parallel to vector a