It is proved that the value of function f (x) = x ^ 6 + x ^ 3 + x ^ 2 + X + 1 is always greater than zero There are additions

It is proved that the value of function f (x) = x ^ 6 + x ^ 3 + x ^ 2 + X + 1 is always greater than zero There are additions

Matching method
f(x)=x^6+x^3+x^2+x+1
=x^6+x^3+0.25 + x^2+x+0.25 +0.5
=(x^3+0.5)^2+(x+0.5)^2+0.5
>0.5>0
Therefore, the value of F (x) = x ^ 6 + x ^ 3 + x ^ 2 + X + 1 is always greater than zero

Elden Ring Premiere

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