When using the image method to solve a system of quadratic equations of two variables, the image of two corresponding functions of one order in the same rectangular coordinate system, the quadratic power of the solution When using image method to solve a system of quadratic equations of two variables, the corresponding images of two quadratic functions are made in the same rectangular coordinate system. The system of quadratic equations of two variables solved is a.x + Y-2 = 0; 3x-2y-1 = 0; b.x + Y-2 = 0; 2x-y-1 = 0 C.2x-y-1=0 ;3x+2y-5=0 D.2x-y-1=0 ; 3x-2y-1=0 Supplementary picture

When using the image method to solve a system of quadratic equations of two variables, the image of two corresponding functions of one order in the same rectangular coordinate system, the quadratic power of the solution When using image method to solve a system of quadratic equations of two variables, the corresponding images of two quadratic functions are made in the same rectangular coordinate system. The system of quadratic equations of two variables solved is a.x + Y-2 = 0; 3x-2y-1 = 0; b.x + Y-2 = 0; 2x-y-1 = 0 C.2x-y-1=0 ;3x+2y-5=0 D.2x-y-1=0 ; 3x-2y-1=0 Supplementary picture

Equation 1 is y = ax + K1, equation 2 is y = BX + K2
∵ equation 1 passes through point (0, - 1) and point P (1,1)
The equation 1 is y = 2x-1
That is, 2x-y-1 = 0
∵ equation 2 passes through points (0,2) and (2,0)
The equation 2 is y = - x + 2
That is, x + Y-2 = 0
So the correct answer is B