Find the inverse function of function y = √ (x-1) + 1 (x ≥ 1)

y=√(x-1)+1(x≥1)
So Y > = 1
y-1=√(x-1)(x≥1,y>=1)
x - 1 = (y-1)^2 = y^2 - 2y + 1
x = y^2 - 2y + 2
The inverse function is y '= x ^ 2 - 2x + 2 (x ≥ 1)

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