The function y = 1 + loga (x + 2) has been inversed Answer with the following formula >> syms x >> y=asin(x)/acos(x); >> diff(y) ans = 1/(1-x^2)^(1/2)/acos(x)+asin(x)/acos(x)^2/(1-x^2)^(1/2)

The original formula is: 1, loga (x + 2) = Y-1; 2, (y + 1) = x + 2; 3, x = a ~ (Y-1) - 2; 4, y = a ~ (x-1) - 2 (a > 0)

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