Given rectangle ABCD, where AB = 5, BC = 8, AE ‖ BD, trapezoid ABDE, find the area of triangle BDE It's a rectangle ABCD with a triangle ade on it,

Because AE is parallel to BD, if BD is the base of triangle abd and bed, the two triangles are equal in height;
The area of two triangles is equal;
Abd area = AB * BD / 2 = 5 * 8 / 2 = 20;

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