On the solution of the equation of first degree with one variable Some of the same rooms need to be painted. Three first-class technicians go to paint eight rooms a day. As a result, 50 square meters of the wall will have to be painted in the future. In the same time, five second-class technicians paint another 40 square meters of the wall in addition to 10 rooms. Each first-class technician paints 10 square meters of the wall in one day more than the second-class technician, so the wall area of each room needs to be painted

On the solution of the equation of first degree with one variable Some of the same rooms need to be painted. Three first-class technicians go to paint eight rooms a day. As a result, 50 square meters of the wall will have to be painted in the future. In the same time, five second-class technicians paint another 40 square meters of the wall in addition to 10 rooms. Each first-class technician paints 10 square meters of the wall in one day more than the second-class technician, so the wall area of each room needs to be painted

The area of the wall to be painted in each room is x square meters
8x-50/3=10x+40/5+10
40x-250=30x+120+150
10x=520
x=52
Answer: each room needs to paint the wall area is 52 square meters