If the circle (x-3) ^ 2 + (y + 2) ^ 2 = 1 is translated according to the vector a = (0, n) and tangent to the straight line y = x + 1, then n=

After translation, the equation is (x-3) ^ 2 + (y + 2-N) ^ 2 = 1, tangent to y = x + 1, that is, the distance from the point (3, n-2) to the straight line is 1. That is, the absolute value of N + 2 is 2 √ (2), n = 2 √ 2-2 or - 2-2 √ 2

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