In RT △ ABC, CD is the bisector of BCE. BCE = 60 °∠ 3 = ∠ 4. Describe the relationship between CB and CE. What's your conjecture? And prove it Note that it's in the RT triangle

It's very simple, two points of De are on AB, ∠ BCE = 60, that is to say, ∠ BEC = 30. In RT △ BCE, the right side of 30 is half of the hypotenuse, so CB = 1 / 2ce
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