In the plane rectangular coordinate system, the coordinate of point a is (√ 3 - √ 2,0), and the coordinate of point C is (- √ 3 - √ 2,0). B is on the Y-axis and s triangle ABC = √ 3, then the coordinate of point B is obtained Help!
|AC|=|√3-√2-(-√3-√2)|=2√3,S△BCA=|AC|*|OB|/2=√3,
2 √ 3 * | ob | / 2 = √ 3, | ob | = 1, coordinates of point B, (0,1) or (0, - 1)
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