As shown in the figure, let △ ABC and △ CDE be equilateral triangles, and ∠ EBD = 62 °, then the degree of ∠ AEB is () °

As shown in the figure, let △ ABC and △ CDE be equilateral triangles, and ∠ EBD = 62 °, then the degree of ∠ AEB is () °

∵ equilateral △ ABC, equilateral △ CDE
∴AC=BC,CE=CD,∠BAC=∠ABC=∠ACB=∠ECD=60
∵∠ACE=∠ACB-∠BCE,∠BCD=∠ECD-∠BCE
∴∠BCD=∠ACE
∴△ACE≌△BCD (SAS)
∴∠CBD=∠CAE
∵∠EBD=62
∴∠CBD=∠EBD-∠CBD=62-∠CBE
∴∠CAE=62-∠CBE
∴∠BAE=∠BAC-∠CAE=60-62+∠CBE=-2+∠CBE
∴∠ABE+∠BAE=60-∠CBE-2+∠CBE=58
∴∠AEB=180-(∠ABE+∠BAE)=122