If AB = 10, eg = 3, then Ag =?

AG=4
Angle GFD = angle a = 60, do DM ⊥ FG through D, cross FG to m, DM = eg = 3
So DF = 2 √ 3
DC = 4 in right triangle DFC
BD=BC-CD=6
Be = 3 in BDE
So Ag = ab-eg-be = 10-3-3 = 4

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