As shown in the figure, △ ABC is an isosceles right triangle, D is the midpoint of AB, ab = 2, sector ADG and BDH are 14 times of the circle with a and B as the center, ad and BD as the radius respectively, then the area of shadow part is______ ．

Connect the CD. The left side of the CD is still, and the right side of the CD is rotated 180 ° clockwise around point d to make point a coincide with point B. after rotation, the graph is butted as shown in the figure above. The area of the shaded part = s semicircle - s △ bef = 12 π· bd2-12be · BF = π − 12, so the answer is: π − 12

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1. As shown in the figure, △ ABC and △ ade are equilateral triangles, and point D is on BC, CF ‖ de intersects AB with F. please explain the size relationship between CF and de
2. As shown in the figure, in RT △ ABC, ∠ a = 90 °, ab = AC = 2, point D is the midpoint of BC side, point E is a moving point on AB side (not coincident with a and b), DF ⊥ de intersects AC at F Let be = x, FC = y （1）DE=DF (2) The functional relation of Y with respect to X and the definition field of X are written out (3) When writing the value of X, EF / / BC
3. As shown in the figure, in RT △ ABC, ∠ ACB = 90 °, ab = 10, BC = 8, point d moves on BC (does not move to B, c), de ‖ AC, intersects AB with E, let BD = x, the area of △ ade is y. (1) find the functional relationship between Y and X and the value range of independent variable x; (2) when x is the value, the area of △ ade is the largest? What is the maximum area?
4. In RT triangle ABC, if ∠ C = 90 °, AC = 6, BC = 8, and G is the center of gravity of △ ABC, then CG =? RT
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6. As shown in the figure, known isosceles △ ABC, AC = BC = 10, ab = 12, take BC as diameter, make ⊙ o intersection AB point D, intersection AC at point G, DF ⊥ AC, perpendicular foot is f, intersection CB extension line at point E. (1) prove: straight line ef is tangent line of ⊙ o; (2) find the value of sin ∠ a
7. As shown in the figure, D, e and F are respectively the midpoint of △ ABC, G is the midpoint of AE, and be intersects DF and DG at P and Q, then PQ: be=______ ．
8. As shown in the figure, in △ ABC, ∠ ACB = 90 °, AC = BC, point D is the midpoint of AB, AE = CF
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